document.write( "Question 795612: Solve by elimination:\r
\n" ); document.write( "\n" ); document.write( "2/3x + 3/4y = 11/12,\r
\n" ); document.write( "\n" ); document.write( "x/3 + 7/18y = 1/2 \n" ); document.write( "
Algebra.Com's Answer #481093 by waynest(281)\"\" \"About 
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(2/3)x + (3/4)y = (11/12)
\n" ); document.write( "(x/3) + (7/18)y = (1/2)
\n" ); document.write( "multiply the second equation by 2 and then subtract it from the first
\n" ); document.write( "(2/3)x + (3/4)y = (11/12)
\n" ); document.write( "(2/3)x + (7/9)y = 1
\n" ); document.write( "you will get
\n" ); document.write( "-(1/36)y = -(1/12)
\n" ); document.write( "-36(-1/36)y = -36(-1/12)
\n" ); document.write( "y = 3
\n" ); document.write( "substitute 3 for y in the first equation to get x
\n" ); document.write( "(2/3)x + (3/4)(3) = (11/12)
\n" ); document.write( "(2/3)x + (9/4) = (11/12)
\n" ); document.write( "(2/3)x + (9/4)- (9/4) = (11/12) - (9/4)
\n" ); document.write( "(2/3)x = (-4/3)
\n" ); document.write( "(3/2)(2/3)x = (-4/3)(3/2)
\n" ); document.write( "x = -2\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "(2/3)(-2) + (3/4)(3) = (11/12)
\n" ); document.write( "(-4/3) + (9/4) = (11/12)
\n" ); document.write( "(11/12) = (11/12)\r
\n" ); document.write( "\n" ); document.write( "(-2/3) + (7/18)(3) = (1/2)
\n" ); document.write( "(-2/3) + (7/6) = (1/2)
\n" ); document.write( "(1/2) = (1/2) \n" ); document.write( "
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