document.write( "Question 67608: A solution of 71% pesticide is to be mixed with a solution of 49% pesticide to form 44 liters of a 51% solution. How much of the 71% solution must you use? \n" ); document.write( "
Algebra.Com's Answer #48107 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A solution of 71% pesticide is to be mixed with a solution of 49% pesticide to form 44 liters of a 51% solution. How much of the 71% solution must you use? \n" ); document.write( "----------- \n" ); document.write( "Amount of 71% solution is \"x\" liters ; amount of active ingredient = 0.71x liters. \n" ); document.write( "Amount of 49% solution is \"44-x\" liters: amount of active ingredient= 0.49( \n" ); document.write( "44-x)= 21.56 -0.49x liters. \n" ); document.write( "------------------ \n" ); document.write( "Amount of mixture is 44 liters ; amount of active ingrediant is 0.51(44)=22.44 liters. \n" ); document.write( "----------------- \n" ); document.write( "EQUATION: \n" ); document.write( "active + active = active \n" ); document.write( "0.71x + 21.56-0.49x = 22.44 \n" ); document.write( "71x+2156 - 49x = 2244 \n" ); document.write( "22x=88 \n" ); document.write( "x=4liters (amount of 71% solution in the mixture) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |