document.write( "Question 795468: how to solve this. 400 pounds of a clay with 1% water. Another clay with 2% is available. How much of 2% clay must you mix with 400 pounds of 1% clay get a 1.4% clay. How much 1.4% clay will you end up?
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Algebra.Com's Answer #481011 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = pounds of 2% clay needed
\n" ); document.write( " $\"+.02x+\"$ = pounds of water in 2% clay
\n" ); document.write( " $\"+.01%2A400+=+4+\"$ pounds of water in 1% clay
\n" ); document.write( "----------------------
\n" ); document.write( " $\"+%28+.02x+%2B+4+%29+%2F+%28+x+%2B+400+%29=+.014+\"$
\n" ); document.write( " $\"+.02x+%2B+4+=+.014%2A%28+x+%2B+400+%29+\"$
\n" ); document.write( " $\"+.02x+%2B+4+=+.014x+%2B+5.6+\"$
\n" ); document.write( " $\"+.006x+=+1.6+\"$
\n" ); document.write( " $\"+x+=+1.6%2F.006+\"$
\n" ); document.write( " $\"+x+=+266.667+\"$
\n" ); document.write( "You end up with $\"+x+%2B+400+\"$ pounds of
\n" ); document.write( "the 1.4% clay
\n" ); document.write( " $\"+x+%2B+400+=+666.667+\"$ pounds
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+%28+.02x+%2B+4+%29+%2F+%28+x+%2B+400+%29=+.014+\"$
\n" ); document.write( " $\"+%28+.02%2A266.667+%2B+4+%29+%2F+%28+266.667+%2B+400+%29=+.014+\"$
\n" ); document.write( " $\"++5.333+%2B+4+=+.014%2A666.667+\"$
\n" ); document.write( " $\"+9.333+=+9.333+\"$
\n" ); document.write( "OK \r
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