document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=795474>Question 795474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 53cm.  If the length is four times the width decreased by 11cm, find its dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #481002 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=481002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 4w - 11<BR>\n" );
document.write( "width = w<BR>\n" );
document.write( "perimeter = 53\r<BR>\n" );
document.write( "\n" );
document.write( "2w + 2(4w - 11) = 53<BR>\n" );
document.write( "2w + 8w - 22 = 53<BR>\n" );
document.write( "19w - 22 + 22 = 53 + 22<BR>\n" );
document.write( "10w = 75<BR>\n" );
document.write( "10w/10 = 75/10<BR>\n" );
document.write( "w = 7.5\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "2(7.5) + 2(4(7.5) - 11) = 53<BR>\n" );
document.write( "15 + 2( 30 - 11) = 53<BR>\n" );
document.write( "15 + 2(19) = 53<BR>\n" );
document.write( "15 + 38 = 53<BR>\n" );
document.write( "53 = 53 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );