document.write( "Question 67560This question is from textbook Beginning Algebra
\n" ); document.write( ": The length of a rectangular playing field is 5 ft less than twice its width.
\n" ); document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field. \n" ); document.write( "
Algebra.Com's Answer #48100 by ankor@dixie-net.com(22740)\"\" \"About 
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Write simple equation for each statement:
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\n" ); document.write( "\"The length of a rectangular playing field is 5 ft less than twice its width.\"
\n" ); document.write( "L = 2W - 5
\n" ); document.write( ":
\n" ); document.write( "\"If the perimeter of the playing field is 230 ft,\"
\n" ); document.write( "2L + 2W = 230
\n" ); document.write( "Simplify, divide equation by 2:
\n" ); document.write( "L + W = 115
\n" ); document.write( ":
\n" ); document.write( "find the length and width of the field.
\n" ); document.write( ":
\n" ); document.write( "Substitute (2W-5) for L in the 2nd equation
\n" ); document.write( "(2W-5) + W = 115
\n" ); document.write( "2W + W = 115 + 5
\n" ); document.write( "3W = 120
\n" ); document.write( "W = 120/3
\n" ); document.write( "W = 40 ft
\n" ); document.write( ":
\n" ); document.write( "Find the length using L = 2W - 5)
\n" ); document.write( "L = 2(40) - 5
\n" ); document.write( "L = 80 - 5
\n" ); document.write( "L = 75 ft
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions using the perimeter:
\n" ); document.write( "2(75) + 2(80) = 230
\n" ); document.write( ":
\n" ); document.write( "Pretty simple, right?
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