document.write( "Question 67593This question is from textbook
\n" ); document.write( ": A bus leaves a station at 1 P.M., traveling west at an average
\n" ); document.write( "rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
\n" ); document.write( "east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart? \n" ); document.write( "

Algebra.Com's Answer #48099 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The 1st question I asked myself is, how far have they gone when they meet?
\n" ); document.write( " $\"d%5B1%5D+=+44%28t+%2B+1%29\"$
\n" ); document.write( " $\"d%5B2%5D+=+48t\"$
\n" ); document.write( "At t = 0
\n" ); document.write( " $\"d%5B1%5D+=+44%7D%7D%0D%0A%7B%7B%7Bd%5B2%5D+=+0\"$
\n" ); document.write( "At t = 1
\n" ); document.write( " $\"d%5B1%5D+=+88%7D%7D%0D%0A%7B%7B%7Bd%5B2%5D+=+48\"$
\n" ); document.write( "At t = 2
\n" ); document.write( " $\"d%5B1%5D+=+132\"$
\n" ); document.write( " $\"d%5B2%5D+=+96\"$
\n" ); document.write( "notice they're getting closer together
\n" ); document.write( "When they meet $\"d%5B1%5D+=+d%5B2%5D\"$
\n" ); document.write( "44(t + 1) = 48t}}}
\n" ); document.write( "48t - 44t = 44}}}
\n" ); document.write( " $\"4t+=+44\"$
\n" ); document.write( " $\"t+=+11\"$
\n" ); document.write( "They meet 11 hours after the 2nd bus leaves,
\n" ); document.write( "12 hours after the 1st bus leaves
\n" ); document.write( " $\"d+=+44%2811+%2B+1%29\"$
\n" ); document.write( " $\"d+=+528\"$ mi
\n" ); document.write( " $\"d+=+48%2A11\"$
\n" ); document.write( " $\"d+=+528\"$ mi so, $\"d%5B1%5D+=+d%5B2%5D\"$
\n" ); document.write( "If they are getting closer together after starting out 44 mi apart,
\n" ); document.write( "they can never be 274 mi apart before they meet
\n" ); document.write( "Let's call their meeting point the new starting line and a new t = 0.
\n" ); document.write( " $\"d%5B1%5D+=+44t\"$
\n" ); document.write( " $\"d%5B2%5D+=+48t\"$
\n" ); document.write( " $\"d%5B2%5D+-+d%5B1%5D+=+274\"$
\n" ); document.write( " $\"48t+-+44t+=+274\"$
\n" ); document.write( " $\"4t+=+274\"$
\n" ); document.write( " $\"t+=+68.5\"$ hrs
\n" ); document.write( " $\"12+%2B+68.5+=+80.5\"$ = hours since 1st bus left at 1 PM
\n" ); document.write( " $\"+80.5+%2F+24+\"$ = 3 days and 8.5 hours
\n" ); document.write( "Add 8.5 to 1 pm to get 9:30 PM 3 days later \r
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