document.write( "Question 795293: The width is a rectangle is three fourths of the length. the perimeter of the rectangle becomes 50cm when the length and the width are each increased by 2cm. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #480985 by ankor@dixie-net.com(22740)\"\" \"About 
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Let W = original width
\n" ); document.write( "Let L = original length
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"The width is a rectangle is three fourths of the length.\"
\n" ); document.write( "W = .75L
\n" ); document.write( ":
\n" ); document.write( "\" the perimeter of the rectangle becomes 50cm when the length and the width are each increased by 2cm.
\n" ); document.write( "2(L+2) + 2(W+2) = 50
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "L + 2 + W + 2 = 25
\n" ); document.write( "L + W + 4 = 25
\n" ); document.write( "L + W = 25 - 4
\n" ); document.write( "L + W = 21
\n" ); document.write( "Replace W with .75L
\n" ); document.write( "L + .75L = 21
\n" ); document.write( "1.75L = 21
\n" ); document.write( "L = 21/1.75
\n" ); document.write( "L = 12 cm is the length
\n" ); document.write( "then obviously
\n" ); document.write( ".75(12) = 9 cm is the width
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check this in the statement:
\n" ); document.write( "\"the perimeter of the rectangle becomes 50cm when the length and the width are each increased by 2cm.\"
\n" ); document.write( "2(14) + 2(11) = 50 \n" ); document.write( "
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