document.write( "Question 795400: The base of a parallelogram is 7ft more than the height. If the area of the parallelogram is 78ft^2, what are the measures of the base and height?
\n" ); document.write( "I would have thought that because we're finding area, the equation would be x(x+7)=78^2... but when I go to solve it doesn't come out correct? Help please? And if you could explain also, that would be wonderful! Thank you!!
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Algebra.Com's Answer #480976 by ankor@dixie-net.com(22740)\"\" \"About 
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The base of a parallelogram is 7ft more than the height.
\n" ); document.write( "If the area of the parallelogram is 78ft^2,
\n" ); document.write( "what are the measures of the base and height?
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\n" ); document.write( "You don't square 78, it just means 78 square ft
\n" ); document.write( "x(x + 7) = 78
\n" ); document.write( "x^2 + 7x - 78 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x+13)(x-6) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "x = 6 ft is the height
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