document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=795352>Question 795352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Keisha has a collection of dimes and nickels worth a total of $4. If she has 50 coins in all, how many nickels does Keisha have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480939 by </B><A HREF=/tutors/aboutme.mpl?userid=sck12><B>sck12(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sck12><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4.00 = x*0.1 + y*0.05\r<BR>\n" );
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document.write( "Work with the y variable first as you know for both to sum to $4.00 the nickels must be a factor of 10. Dealing with dimes will always be in factors of 10. \r<BR>\n" );
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document.write( "x= 30 dimes y = 20 nickels </SPAN>\n" );
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