document.write( "Question 795376: A collection of nickels (x), dimes (y), and quarters (z) consist of 85 coins with a total of $10.25. If there are 2 times as many dimes as quarters, find the number of each type. \n" ); document.write( "

Algebra.Com's Answer #480934 by sunny1992(35) $\"\"$ $\"About$

You can put this solution on YOUR website!
1 nickel = 5cents
\n" ); document.write( "1 dime = 10cents
\n" ); document.write( "1 quarter = 25 cents
\n" ); document.write( "$10.25 = 1025 cents\r
\n" ); document.write( "\n" ); document.write( "x+y+z = 85 -----> eq1
\n" ); document.write( "5x+10y+25z = 1025 ----> eq2
\n" ); document.write( "y=2z\r
\n" ); document.write( "\n" ); document.write( "putting y=2z in eq 1
\n" ); document.write( "x+2z+z=85
\n" ); document.write( "x+3z=85
\n" ); document.write( "x=85-3z\r
\n" ); document.write( "\n" ); document.write( "putting x=85-3z & y=2z in eq 2
\n" ); document.write( "5(85-3z)+10(2z)+25z=1025
\n" ); document.write( "425-15z+20z+25z=1025
\n" ); document.write( "30z=1025-425
\n" ); document.write( "30z=600
\n" ); document.write( " $\"+z=600%2F30+\"$
\n" ); document.write( "z=20\r
\n" ); document.write( "\n" ); document.write( "y=2z=2(20)=40\r
\n" ); document.write( "\n" ); document.write( "x=85-3z=85-3(20)=25 \n" ); document.write( "

\n" );