document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=795385>Question 795385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve using substitution method\r<BR>\n" );
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document.write( "x+y=2<BR>\n" );
document.write( "x-y=-2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480932 by </B><A HREF=/tutors/aboutme.mpl?userid=wilft1><B>wilft1(217)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wilft1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=wilft1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cant really solve this using substitution, you can solve it using the subtraction/addition method...\r<BR>\n" );
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document.write( "x + y = 2<BR>\n" );
document.write( "x - y = -2\r<BR>\n" );
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document.write( "add the lines together to get...\r<BR>\n" );
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document.write( "x = 0\r<BR>\n" );
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document.write( "plug that number into the original equation to find the value of y\r<BR>\n" );
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document.write( "0 + y = 2<BR>\n" );
document.write( "0 - y = -2\r<BR>\n" );
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document.write( "y = 2\r<BR>\n" );
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document.write( "leave your answer in ordered pair  (0,2) </SPAN>\n" );
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