document.write( "Question 795373: invested part of my 22000 dollar advance at 5% annual simple interest and the rest at 6% annual simple interest if my yearly interest from both accounts is 1,310 dollars what is the amount invested at each rate \n" ); document.write( "

Algebra.Com's Answer #480928 by sunny1992(35) $\"\"$ $\"About$

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suppose on 5% annual interest you invested X amount
\n" ); document.write( "so on 6% annual interest you have invested remaining that is 22000-X
\n" ); document.write( "(Xx5%)+[(22000-X)x6%)]=1,310
\n" ); document.write( "5%X + 1320 - 6%X = 1310
\n" ); document.write( "-1%X=1310 - 1320
\n" ); document.write( "-1%X = -10
\n" ); document.write( " $\"+X=+-10%2F-1%25+\"$
\n" ); document.write( "X = 10 x 100
\n" ); document.write( "X= 1000 \n" ); document.write( "

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