document.write( "Question 795330: A chemistry student needs 600 ml of a 6% solution. How much 10% and 4% solutions need to be mixed? \n" ); document.write( "
Algebra.Com's Answer #480902 by wilft1(217)\"\" \"About 
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this one is solved with 2 equations\r
\n" ); document.write( "\n" ); document.write( "x + y = 600
\n" ); document.write( "10x + 4y = 6
\n" ); document.write( "multiply 600 by 6
\n" ); document.write( "x + y = 600
\n" ); document.write( "10x + 4y = 3600
\n" ); document.write( "multiply the top line by -4
\n" ); document.write( "-4x - 4y = -2400
\n" ); document.write( "10x + 4y = 3600
\n" ); document.write( "add the two lines together
\n" ); document.write( "6x = 1200
\n" ); document.write( "divide both sides by 6
\n" ); document.write( "x = 200
\n" ); document.write( "now that we know the value for x, plug that into the original equation
\n" ); document.write( "10(200) + 4y = 3600
\n" ); document.write( "2000 + 4y = 3600
\n" ); document.write( "4y = 1600
\n" ); document.write( "y = 400
\n" ); document.write( "x = 200, y = 400
\n" ); document.write( "so you will need 200 ml of the 10 percent solution and 400 ml of the 4 percent solution
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