document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=795284>Question 795284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.) Alice is twice as old as Jimmy. In Twelve years, the sum of their ages is 99. How old is each now?\r<BR>\n" );
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document.write( "2.) A certain doctor's age is no 7/9 of what it will be 18 years from now. Just how old is he now?\r<BR>\n" );
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document.write( "3.) The sum of the ages of a father and her daughter is 44 years old. The father's age is 4 years more than 3 times the daughter's age. find the ages of both. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480896 by </B><A HREF=/tutors/aboutme.mpl?userid=wilft1><B>wilft1(217)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wilft1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=wilft1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first one<BR>\n" );
document.write( "x + 2x + 12 + 12 = 99 (in twelve years the sum of their ages is 99, there are two of them, thats why i put in 12 + 12)\r<BR>\n" );
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document.write( "combine like terms...<BR>\n" );
document.write( "3x + 24 = 99<BR>\n" );
document.write( "subtract 24 from both sides<BR>\n" );
document.write( "3x = 75<BR>\n" );
document.write( "divide both sides by 3<BR>\n" );
document.write( "x = 25<BR>\n" );
document.write( "jimmy is 25, alice is 50<BR>\n" );
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document.write( "doc is 7/9 of what he will be 18 years from now.  that tells me that 18 is 2/9 of his age in the future, so multiply 18 x 4.5 = 81 (4.5 is how many times 2 will go into 9 and make the fraction a whole number).  you can make it a little easier by saying that it will be 9 of 1/9, so just multiply 9 x 9 = 81.   18 years from now he will be 81, so subtract 18 from 81 to learn that his current age is 63.<BR>\n" );
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document.write( "father is 4 years more than 3 times his daughters age, equals out to 44 years old... the formula for this...<BR>\n" );
document.write( "x + 3x + 4 = 44<BR>\n" );
document.write( "subtract 4 from both sides...<BR>\n" );
document.write( "x + 3x = 40<BR>\n" );
document.write( "combine like terms<BR>\n" );
document.write( "4x = 40<BR>\n" );
document.write( "divide both sides by 4<BR>\n" );
document.write( "x = 10<BR>\n" );
document.write( "daughter is 10 years old, daddy is 30 years old\r<BR>\n" );
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document.write( "hope this helps :) </SPAN>\n" );
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