document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67580>Question 67580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Farmer Fred has goats and chickens in his fenced barnyard. Tiny Tim can only see under the fence and he counts 72 feet. Tall Tony can see over the fence and he counts 26 heads. How many chickens does Farmer Fred have in his barnyard?\r<BR>\n" );
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document.write( "thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48088 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> g+c=26 counting heads<BR>\n" );
document.write( "4g+2c=72 counting feet<BR>\n" );
document.write( "if we multiply the ehad count by -2 and add we get the following<BR>\n" );
document.write( "-2g-2c=-52<BR>\n" );
document.write( "4g+2c=72<BR>\n" );
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document.write( "2g=20<BR>\n" );
document.write( "g=10 count of goats thus<BR>\n" );
document.write( "10+c=26<BR>\n" );
document.write( "c=26-10<BR>\n" );
document.write( "c=16 count of chickens<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "4*10+2*16=72<BR>\n" );
document.write( "40+32=72<BR>\n" );
document.write( "72=72<BR>\n" );
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