document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=795277>Question 795277</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a triangle i 3 inches less than its length, and the area is 108 square inches.what are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480860 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the width of a triangle is 3 inches less than its length, and the area is 108 square inches.what are the length and width of the rectangle?<BR>\n" );
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document.write( "Let length be L<BR>\n" );
document.write( "Then width = L-3<BR>\n" );
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document.write( "Area = length*width <BR>\n" );
document.write( "108 = L(L-3)<BR>\n" );
document.write( "L^2 - 3L - 108 = 0<BR>\n" );
document.write( "(L-12)(x+9) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "Length = 12 inches<BR>\n" );
document.write( "Width = L-3 = 9 inches<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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