document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=795155>Question 795155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hector is performing an experiment that requires 160 ml of 40% sulfuric solution.  He has a 25% sulfuric acid solution and a 50% sulfuric acid solution.  How many ml of each solution should he mix to obtain the needed solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480824 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hector is performing an experiment that requires 160 ml of 40% sulfuric solution. He has a 25% sulfuric acid solution and a 50% sulfuric acid solution. How many ml of each solution should he mix to obtain the needed solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.25x + 0.50(160-x) = 0.40*160<BR>\n" );
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document.write( "25x + 50*160 - 50x = 40*160<BR>\n" );
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document.write( "-25x = -10*160<BR>\n" );
document.write( "x = (2/5)160<BR>\n" );
document.write( "x = 64 ml (amt. of 25% solution needed)<BR>\n" );
document.write( "160-x = 96 ml (amt. of 50% solution needed)<BR>\n" );
document.write( "==========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------------------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );