document.write( "Question 67429: 3x+2y=22 2x+3y=23 using the simultaneous method find the values of x and y which satisfy the equation \n" ); document.write( "

Algebra.Com's Answer #48076 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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3x+2y=22 2x+3y=23 using the simultaneous method find the values of x and y which satisfy the equation
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\n" ); document.write( "3x + 2y = 22
\n" ); document.write( "2x + 3y = 23
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\n" ); document.write( "Multiply eq one by 3 and eq two by 2 and you have:
\n" ); document.write( "9x + 6y = 66
\n" ); document.write( "4x + 6y = 46
\n" ); document.write( "-----------------Subtracting eliminates y
\n" ); document.write( "5x + 0y = 20
\n" ); document.write( "5x = 20
\n" ); document.write( "x = 20/5; divided both sides by 5
\n" ); document.write( "x = 4
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\n" ); document.write( "Find y using equation one:
\n" ); document.write( "3x + 2y = 22
\n" ); document.write( "3(4) + 2y = 22
\n" ); document.write( "12 + 2y = 22
\n" ); document.write( "2y = 22 - 12, subtracted 12 from both sides
\n" ); document.write( "2y = 10
\n" ); document.write( "y = 10/2; divided both sides by 2
\n" ); document.write( "y = 5
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\n" ); document.write( "Check solutions in equation two
\n" ); document.write( "2x + 3y = 23
\n" ); document.write( "2(4) + 3(5) = 23
\n" ); document.write( "8 + 15 = 23
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