document.write( "Question 794830: If y = 2^-x, find x if y = 0.0625 \n" ); document.write( "
Algebra.Com's Answer #480743 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
0.0625 = 2^-x
\n" ); document.write( "log 0.0625 = -x log 2
\n" ); document.write( "log 0.0625/log 2 = -x
\n" ); document.write( "-4 = -x
\n" ); document.write( "x = 4
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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