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equation of hyperbola is given by the equation 8y2-2x2=16. find the co ordinates of.
\n" ); document.write( "1) foci
\n" ); document.write( "2) vertices
\n" ); document.write( "3) eccentricity
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\n" ); document.write( "8y^2-2x^2=16
\n" ); document.write( "y^2/2-x^2/8=1
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis and center at (0,0)
\n" ); document.write( "Its standard form of equation: y^2/a^2-x^2/b^2=1
\n" ); document.write( "..
\n" ); document.write( "a^2=2
\n" ); document.write( "a=√2
\n" ); document.write( "b^2=8
\n" ); document.write( "b=√8
\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "c^2=2+8=10
\n" ); document.write( "c=√10≈3.16
\n" ); document.write( "..
\n" ); document.write( "1) foci:(0,0±c)=(0,0±3.16)=(0,0-3.16) and (0,0+3.16)
\n" ); document.write( "2) vertices:(0,0±a)=(0,0±√2)=(0,0-√2)and (0,0+√2)
\n" ); document.write( "3) eccentricity: c/a=√10/√2=√5\r
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