document.write( "Question 794653: The width of a rectangle is 1 inch more then twice it's length, and the perimeter is is 104 inches. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #480688 by waynest(281)\"\" \"About 
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width = 2L + 1
\n" ); document.write( "length = L
\n" ); document.write( "p = 104
\n" ); document.write( "2L + 2(2L + 1) = 104
\n" ); document.write( "2L + 4L + 2 = 104
\n" ); document.write( "6L + 2 - 2 = 104 - 2
\n" ); document.write( "6L = 102
\n" ); document.write( "6L/6 = 102/6
\n" ); document.write( "L = 17\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "2(17) + 2(2(17) + 1) = 104
\n" ); document.write( "34 + 2(34 + 1) = 104
\n" ); document.write( "34 + 68 + 2 = 104
\n" ); document.write( "104 = 104
\n" ); document.write( "
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