document.write( "Question 794251: A ski lift carried Maria up a slope at a rate of 6 km/h, and she skied back down parallel to the lift at 34 km/h. The round trip took 30 min. How far did she ski and for how long? \n" ); document.write( "

Algebra.Com's Answer #480677 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A ski lift carried Maria up a slope at a rate of 6 km/h, and she skied back down parallel to the lift at 34 km/h.
\n" ); document.write( " The round trip took 30 min.
\n" ); document.write( " How far did she ski and for how long?
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\n" ); document.write( "Change 30 min to .5 hrs
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\n" ); document.write( "Let d = distance up and distance down
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\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "time up + time down = .5 hrs
\n" ); document.write( " $\"d%2F6\"$ + $\"d%2F34\"$ = .5
\n" ); document.write( "Multiply by the least common multiple: 102
\n" ); document.write( "102* $\"d%2F6\"$ + 102* $\"d%2F34\"$ = 102(.5)
\n" ); document.write( "Cancel the denominators
\n" ); document.write( "17d + 3d = 51
\n" ); document.write( "20d = 51
\n" ); document.write( "d = 51/20
\n" ); document.write( "d = 2.55 km she skied
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\n" ); document.write( "Find her time down the hill
\n" ); document.write( "2.55/34 = .075 hrs which is: .075(60) = 4.5 minutes
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\n" ); document.write( "Check this by finding the time up:
\n" ); document.write( "2.55/6 = .425 hrs
\n" ); document.write( ".425 + .075 = .5 Which is 30 min \n" ); document.write( "

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