document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67531>Question 67531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48066 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A bus(A SAY) leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later <BR>\n" );
document.write( "DISTANCE TRAVELED BY A IN 1 HR=44*1=44 MILES\r<BR>\n" );
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document.write( "a second bus(B SAY) leaves the same station, traveling east at a rate of 48 mi/h.<BR>\n" );
document.write( "HENCE INITIAL DISTANCE OF SEPARATION BETWEEN A & B = 44 MILES\r<BR>\n" );
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document.write( " At what time will the two buses be 274 mi apart?<BR>\n" );
document.write( "FINAL DISTANCE OF SEPARATION BETWEEN A AND B =274 MILES<BR>\n" );
document.write( "HENCE DIFFERENCE IN DISTANCE =274-44=230 MILES<BR>\n" );
document.write( "A AND B ARE TRAVELING IN OPPOSITE DIRECTIONS...SO <BR>\n" );
document.write( "RELATIVE SPEED = 44+48=92 MPH<BR>\n" );
document.write( "TIME = 230/92=2.5 HRS.<BR>\n" );
document.write( "HENCE THE 2 BUSES WILL BE 274 MILES APART AT 1=00 PM +1 HR + 2.5 HRS =4.5 PM<BR>\n" );
document.write( "4=30 PM<BR>\n" );
document.write( " </SPAN>\n" );
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