document.write( "Question 67532: Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? \n" ); document.write( "

Algebra.Com's Answer #48063 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
We'll determine how many hours it takes John to catch up and then add that to 11:00am-------------that will give us the answer\r
\n" ); document.write( "\n" ); document.write( "When the distances that both Martina and John have travelled are the same, then John will have caught up.\r
\n" ); document.write( "\n" ); document.write( "distance (d)=rate(r) times time(t)\r
\n" ); document.write( "\n" ); document.write( "d=rt
\n" ); document.write( "let t= time that has elapsed since John started
\n" ); document.write( "then (t+2) Martina's elapsed time\r
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\n" ); document.write( "\n" ); document.write( "Martina's Distance=24mph(t+2)\r
\n" ); document.write( "\n" ); document.write( "Johns Distance=48t\r
\n" ); document.write( "\n" ); document.write( "When the distances that both Martina and John have travelled are the same, then John will have caught up.
\n" ); document.write( "24(t+2)=48t
\n" ); document.write( "24t+48=48t subtract 24t from both sides:
\n" ); document.write( "48=24t
\n" ); document.write( "t=2 hours-----------------'till they are both at the same place\r
\n" ); document.write( "\n" ); document.write( "11:00am+2 hours=1:00pm------------------------the answer we are looking for\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "Martina's Distance=24mph(t+2)=24(4)=96 mi\r
\n" ); document.write( "\n" ); document.write( "Johns Distance=48t=48(2)=96 mi \r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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