document.write( "Question 794179: in 6 hours A travels 10 Km more THAN B DOES IN 5 HOURS;AND IN 8 hours B travels 7 Km more than A does in 5 hours.WHAT ARE THE SPEEDS OF A AND B. \n" ); document.write( "
Algebra.Com's Answer #480626 by ankor@dixie-net.com(22740)\"\" \"About 
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Let a = A's speed
\n" ); document.write( "Let b = B's
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\n" ); document.write( "\n" ); document.write( "Write a distance equation for each statement, (Dist = time * speed):
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\n" ); document.write( "In 6 hours A travels 10 Km more THAN B DOES IN 5 HOURS;
\n" ); document.write( "6a - 5b = 10
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\n" ); document.write( "IN 8 hours B travels 7 Km more than A does in 5 hours.
\n" ); document.write( "8b - 5a = 7
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\n" ); document.write( "Arrange equations for elimination
\n" ); document.write( "6a - 5b = 10
\n" ); document.write( "-5a+ 8b = 7
\n" ); document.write( "Multiply the 1st equation by 8, the 2nd equation by 5
\n" ); document.write( "48a - 40b = 80
\n" ); document.write( "-25a + 40b = 35
\n" ); document.write( "------------------adding eliminates b find a
\n" ); document.write( "23a = 115
\n" ); document.write( "a = 115/23
\n" ); document.write( "a = 5 km/hr is A's speed
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\n" ); document.write( "Find b using the 1st equation
\n" ); document.write( "6(5) - 5b = 10
\n" ); document.write( "-5b = 10 - 30
\n" ); document.write( "-5b = -20
\n" ); document.write( "b = -20/-5
\n" ); document.write( "b = + 4 km/hr is B's speed
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\n" ); document.write( "Check this in the 2nd equation
\n" ); document.write( "8(4) - 5(5) = 7
\n" ); document.write( "32 - 25 = 7 \r
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