document.write( "Question 794179: in 6 hours A travels 10 Km more THAN B DOES IN 5 HOURS;AND IN 8 hours B travels 7 Km more than A does in 5 hours.WHAT ARE THE SPEEDS OF A AND B. \n" ); document.write( "
Algebra.Com's Answer #480626 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let a = A's speed \n" ); document.write( "Let b = B's \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "Write a distance equation for each statement, (Dist = time * speed): \n" ); document.write( ": \n" ); document.write( "In 6 hours A travels 10 Km more THAN B DOES IN 5 HOURS; \n" ); document.write( "6a - 5b = 10 \n" ); document.write( ": \n" ); document.write( "IN 8 hours B travels 7 Km more than A does in 5 hours. \n" ); document.write( "8b - 5a = 7 \n" ); document.write( ": \n" ); document.write( "Arrange equations for elimination \n" ); document.write( "6a - 5b = 10 \n" ); document.write( "-5a+ 8b = 7 \n" ); document.write( "Multiply the 1st equation by 8, the 2nd equation by 5 \n" ); document.write( "48a - 40b = 80 \n" ); document.write( "-25a + 40b = 35 \n" ); document.write( "------------------adding eliminates b find a \n" ); document.write( "23a = 115 \n" ); document.write( "a = 115/23 \n" ); document.write( "a = 5 km/hr is A's speed \n" ); document.write( ": \n" ); document.write( "Find b using the 1st equation \n" ); document.write( "6(5) - 5b = 10 \n" ); document.write( "-5b = 10 - 30 \n" ); document.write( "-5b = -20 \n" ); document.write( "b = -20/-5 \n" ); document.write( "b = + 4 km/hr is B's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the 2nd equation \n" ); document.write( "8(4) - 5(5) = 7 \n" ); document.write( "32 - 25 = 7 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( " |