document.write( "Question 67535: There are 850 Douglas fir and ponderosa pine trees in a section of forest bought by Sawz Logging Co. The company paid an average of $300 for each Douglas $217,500 for the trees, how many of each kind did the company buy? \n" ); document.write( "
Algebra.Com's Answer #48060 by ptaylor(2198) You can put this solution on YOUR website! \n" ); document.write( "I BELIEVE THE COST OF OF EACH PONDEROSA WAS ACCIDENTLY OMITTED FROM THIS PROBLEM. IF IT WAS, THEN SUBSTITUTE THAT VALUE INTO THE EQUATION FOR Z. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x=number of Douglas Fir \n" ); document.write( "Then 850-x=number of Ponderosa \n" ); document.write( "$300=cost of each Douglas Fir \n" ); document.write( "$Z=cost of each Ponderosa (I BELIEVE THAT THIS VALUE SHOULD HAVE BEEN GIVEN) \n" ); document.write( "We know that Z(850-x)=total cost of the Ponderosa \n" ); document.write( "And $300x=total cost of of the Douglas Fir\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we are told that the total cost of the ponderosa Z(850-x) plus the total cost of the Douglas Fir 300x equals $217,500. So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "Z(850-x)+300x=$217,500 clear the parens:\r \n" ); document.write( "\n" ); document.write( "850Z-Zx+300x=$217,500 subtract 850Z from both sides:\r \n" ); document.write( "\n" ); document.write( "300x-Zx=$217,500-850Z \n" ); document.write( "x(300-Z)=217,500-850Z divide both sides by (300-Z)\r \n" ); document.write( "\n" ); document.write( "x=(217,500-850Z)/(300-Z)-------------number of Douglas Fir \n" ); document.write( "850-x equals------------------------number of Ponderosa\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |