document.write( "Question 793872: A 24 feet long iron pipe has 20 kgs of weight. I want to balance this pipe from the point which is 3 feet from one end side and 21 feet at another end. so How much weight should I put on small end to balance it ? \n" ); document.write( "

Algebra.Com's Answer #480599 by KMST(5328) $\"\"$ $\"About$

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The 3 feet of pipe to one side of the fulcrum balance the 3ft of pipe to the other side.
\n" ); document.write( "The weight (x kg) put on the small end, has to balance the 18 feet of pipe extending from 3 to 21 feet away from the fulcrum.
\n" ); document.write( "That 18-foot stretch of pipe is 18/24=3/4 of the entire pipe and weighs
\n" ); document.write( "(3/4)(20kg)=15kg
\n" ); document.write( "The weight could be considered applied at the midpoint, (3ft+21ft)/2=12ft from the fulcrum.
\n" ); document.write( "The torque produced by that weight and the torque produced by the balancing weight on the short end (at 3 ft from the fulcrum) should have the same magnitude, so
\n" ); document.write( "(3ft)(x kg) = (12ft)(15kg) --> x kg = 15kg (12ft/3ft = 4(15kg) = 60kg
\n" ); document.write( "You need a 60 kg weight applied on the small end to balance the pipe. \n" ); document.write( "

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