document.write( "Question 67542: Find two consecutive positive integers such that the sum of their squares is 85. [You must use algebra to solve this, setting up an equation with a variable, and using algebra to solve for the variable.]\r
\n" ); document.write( "\n" ); document.write( "This one has me so confused. I need help, please????
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Algebra.Com's Answer #48056 by 303795(602)\"\" \"About 
You can put this solution on YOUR website!
If the first number is x then the consecutive number will be x+1.\r
\n" ); document.write( "\n" ); document.write( "The squares of these two numbers add to 85 so
\n" ); document.write( "\"x%5E2+%2B+%28x%2B1%29%5E2=85\"
\n" ); document.write( "\"x%5E2+%2B+x%5E2+%2B+2x+%2B1=85\"
\n" ); document.write( "\"2x%5E2++%2B+2x+%2B+1+=+85\"
\n" ); document.write( "\"2x%5E2++%2B+2x+-+84+=0\"
\n" ); document.write( "Divide each side of the equation by 2
\n" ); document.write( "\"x%5E2++%2B+x+-+42+=0\"
\n" ); document.write( "factorise
\n" ); document.write( "\"%28x%2B7%29%28x-6%29+=0\"
\n" ); document.write( "So x=-7 or x=6
\n" ); document.write( "The problem states that the numbers are positive so x=6.
\n" ); document.write( "The consecutive numbers are therefore 6 and 7 (\"6%5E2%2B7%5E2=36%2B49=85\")
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