document.write( "Question 793897: Four years ago Bob was twice as old as his little sister. Five years from now he will six years older than his sister. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #480480 by sunny1992(35)\"\" \"About 
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let,
\n" ); document.write( "little sister age = X
\n" ); document.write( "Bob age= 2X\r
\n" ); document.write( "\n" ); document.write( "current age
\n" ); document.write( "sister's age = X+4
\n" ); document.write( "Bob age = 2X+4\r
\n" ); document.write( "\n" ); document.write( "After 5 years
\n" ); document.write( "sister age= X+4+5
\n" ); document.write( "Bob age = X+4+5+6 (six year older than sister) OR 2x+4+5\r
\n" ); document.write( "\n" ); document.write( "so,
\n" ); document.write( "X+4+5+6=2x+4+5
\n" ); document.write( "X+15=2X+9
\n" ); document.write( "X=6\r
\n" ); document.write( "\n" ); document.write( "Sister's current age= 6+4= 10
\n" ); document.write( "Bob Current age= 12+4=16\r
\n" ); document.write( "\n" ); document.write( "for any query contact at kool_sunny92@hotmail.com
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