document.write( "Question 793897: Four years ago Bob was twice as old as his little sister. Five years from now he will six years older than his sister. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #480480 by sunny1992(35)![]() ![]() You can put this solution on YOUR website! let, \n" ); document.write( "little sister age = X \n" ); document.write( "Bob age= 2X\r \n" ); document.write( "\n" ); document.write( "current age \n" ); document.write( "sister's age = X+4 \n" ); document.write( "Bob age = 2X+4\r \n" ); document.write( "\n" ); document.write( "After 5 years \n" ); document.write( "sister age= X+4+5 \n" ); document.write( "Bob age = X+4+5+6 (six year older than sister) OR 2x+4+5\r \n" ); document.write( "\n" ); document.write( "so, \n" ); document.write( "X+4+5+6=2x+4+5 \n" ); document.write( "X+15=2X+9 \n" ); document.write( "X=6\r \n" ); document.write( "\n" ); document.write( "Sister's current age= 6+4= 10 \n" ); document.write( "Bob Current age= 12+4=16\r \n" ); document.write( "\n" ); document.write( "for any query contact at kool_sunny92@hotmail.com \n" ); document.write( " |