document.write( "Question 793853: The length of a rectangle is 4 less than 3 times the width. If the
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document.write( "perimeter is 56 inches, what is the area of the rectangle? \n" );
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Algebra.Com's Answer #480470 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! P = Lw \n" ); document.write( "length (L) = 3w - 4 \n" ); document.write( "width (w) \n" ); document.write( "Perimeter = 56\r \n" ); document.write( "\n" ); document.write( "2w + 2(3w -4) = 56 \n" ); document.write( "2w + 6w - 8 = 56 \n" ); document.write( "8w - 8 + 8 = 56 + 8 \n" ); document.write( "8w = 64 \n" ); document.write( "8w/8 = 64/8 \n" ); document.write( "w = 8 \n" ); document.write( "length = 3(8) - 4 \n" ); document.write( " = 24 - 4 \n" ); document.write( " = 20 \n" ); document.write( "check: \n" ); document.write( "2(8) + 2(3(8) - 4) = 56 \n" ); document.write( "16 + 2(24 - 4) = 56 \n" ); document.write( "16 + 2(20) = 56 \n" ); document.write( "16 + 40 = 56 \n" ); document.write( "56 = 56 \n" ); document.write( "Area = Lw \n" ); document.write( " = 20 * 8 \n" ); document.write( " = 160 in^2 \n" ); document.write( " |