document.write( "Question 793853: The length of a rectangle is 4 less than 3 times the width. If the
\n" ); document.write( "perimeter is 56 inches, what is the area of the rectangle?
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Algebra.Com's Answer #480470 by waynest(281)\"\" \"About 
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P = Lw
\n" ); document.write( "length (L) = 3w - 4
\n" ); document.write( "width (w)
\n" ); document.write( "Perimeter = 56\r
\n" ); document.write( "\n" ); document.write( "2w + 2(3w -4) = 56
\n" ); document.write( "2w + 6w - 8 = 56
\n" ); document.write( "8w - 8 + 8 = 56 + 8
\n" ); document.write( "8w = 64
\n" ); document.write( "8w/8 = 64/8
\n" ); document.write( "w = 8
\n" ); document.write( "length = 3(8) - 4
\n" ); document.write( " = 24 - 4
\n" ); document.write( " = 20
\n" ); document.write( "check:
\n" ); document.write( "2(8) + 2(3(8) - 4) = 56
\n" ); document.write( "16 + 2(24 - 4) = 56
\n" ); document.write( "16 + 2(20) = 56
\n" ); document.write( "16 + 40 = 56
\n" ); document.write( "56 = 56
\n" ); document.write( "Area = Lw
\n" ); document.write( " = 20 * 8
\n" ); document.write( " = 160 in^2
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