document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=793818>Question 793818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A taxi charges P30 for the first half kilometer and P10 for each additional 200 meters. How far in kilometers can a person ride and owe between P130 and P280? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480456 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A taxi charges P30 for the first half kilometer and P10 for each additional 200 meters. How far in kilometers can a person ride and owe between P130 and P280?<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "p30 + p10(x) = P130<BR>\n" );
document.write( "p10(x) = P100<BR>\n" );
document.write( "x = 10 <BR>\n" );
document.write( "Total distance for P130 = (1/2)km + 10(200)meters = (1/2)+2 = 2.5km\r<BR>\n" );
document.write( "\n" );
document.write( "-------<BR>\n" );
document.write( "P30 + p(10)x = P280<BR>\n" );
document.write( "p(10)x = P250<BR>\n" );
document.write( "x = 25<BR>\n" );
document.write( "Total distance for P280 = (1/2)km + 25(200)meters = (1/2) + 5 = 5.5km<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Ans: He can ride between 2.5km and 5.5km<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "====================<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );