document.write( "Question 793800: Bob is three times older than Alice. Ten years ago Bob's age was twice that what Alice's age will be in 5 years. How old are Bob and Alice now? \n" ); document.write( "
Algebra.Com's Answer #480444 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Bob is three times older than Alice. \n" ); document.write( "B = 3A \n" ); document.write( "Ten years ago Bob's age was twice that what Alice's age will be in 5 years. \n" ); document.write( "B - 10 = 2(A + 5) \n" ); document.write( "Replace B with 3A from first equation. \n" ); document.write( "3A - 10 = 2(A + 5) \n" ); document.write( "3A - 10 = 2A + 10 \n" ); document.write( "Collect like terms \n" ); document.write( "3A - 2A = 10 + 10 \n" ); document.write( "A = 20 \n" ); document.write( "Currently; \n" ); document.write( "Alice is 20 years old \n" ); document.write( "Bob is 60 years old. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |