document.write( "Question 793800: Bob is three times older than Alice. Ten years ago Bob's age was twice that what Alice's age will be in 5 years. How old are Bob and Alice now? \n" ); document.write( "
Algebra.Com's Answer #480444 by Cromlix(4381)\"\" \"About 
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Bob is three times older than Alice.
\n" ); document.write( "B = 3A
\n" ); document.write( "Ten years ago Bob's age was twice that what Alice's age will be in 5 years.
\n" ); document.write( "B - 10 = 2(A + 5)
\n" ); document.write( "Replace B with 3A from first equation.
\n" ); document.write( "3A - 10 = 2(A + 5)
\n" ); document.write( "3A - 10 = 2A + 10
\n" ); document.write( "Collect like terms
\n" ); document.write( "3A - 2A = 10 + 10
\n" ); document.write( "A = 20
\n" ); document.write( "Currently;
\n" ); document.write( "Alice is 20 years old
\n" ); document.write( "Bob is 60 years old.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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