document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=793645>Question 793645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 64 liters containing 55% acid, using 3 times as much of the 75% solution as the 35% solution. How many liters of each solution should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480397 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 64 liters containing 55% acid, using 3 times as much of the 75% solution as the 35% solution. How many liters of each solution should be used?\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid + acid = acid<BR>\n" );
document.write( "x + y + z = 64<BR>\n" );
document.write( "0.25x + 0.35y + 0.75z = 0.55*64<BR>\n" );
document.write( "z = 3y<BR>\n" );
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document.write( "x + y + 3y = 64<BR>\n" );
document.write( "0.25x + 0.35y + 0.75(3y) = 0.55*64<BR>\n" );
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document.write( "x + 4y = 64<BR>\n" );
document.write( "0.25x + 2.6y = 35.2<BR>\n" );
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document.write( "25x + 100y = 1600<BR>\n" );
document.write( "25x + 260y = 3520<BR>\n" );
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document.write( "Solve for \"y\":<BR>\n" );
document.write( "160y = 1920<BR>\n" );
document.write( "y = 12 liters (amt. of 35% solution needed)<BR>\n" );
document.write( "x = 3y = 36 liters (amt. of 25% solution needed)<BR>\n" );
document.write( "z = 64-12-36 = 16 liters (amt. of 75% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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