document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=793391>Question 793391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorist travelling at 80 km/hr is being chased by a police car at 148 km/hr. If the police car starts from 3.5 km back, how long does it take to catch the motorist? Leave time in hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480349 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let t = time it takes the police car to catch up to the speeding motorist.<BR>\n" );
document.write( "During that time the speeder travels a distance d given by<BR>\n" );
document.write( "(1)  d = 80t while the policy car travels that distance plus 3.5km or<BR>\n" );
document.write( "(2) d + 3.5 = 148t<BR>\n" );
document.write( "Put (1) into (2) to get<BR>\n" );
document.write( "(3) 148t = 80t + 3.5 or<BR>\n" );
document.write( "(4) 68t = 3.5 or<BR>\n" );
document.write( "(5) t = 0.0514... <BR>\n" );
document.write( "Answer: The police car takes 0.0514+ hours to catch up to the speeder. </SPAN>\n" );
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