document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67501>Question 67501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> right triangle.the longest side of a right triangle is 3 inches less than twice the shortest side.the third side measures 12 inches.find the length ot the shortest side </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48033 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X^2+12^2=(2X-3)^2<BR>\n" );
document.write( "X^2+144=4X^2-12X+9<BR>\n" );
document.write( "X^2-4X^2+12X+135=0<BR>\n" );
document.write( "-3X^2+8X+135=0<BR>\n" );
document.write( "3X^2-8X-135=0 USING THE QUADRATIC EQUATION WE GET:<BR>\n" );
document.write( "X=(-B+-SQRT[B^2-4AC])/2A<BR>\n" );
document.write( "X=(8+-SQRT[64-4*3*-135])/2*3<BR>\n" );
document.write( "X=(8+-SQRT[64+1620])/6<BR>\n" );
document.write( "X=(8+-SQRT1684)/6<BR>\n" );
document.write( "X=(8+-41.036457)/6<BR>\n" );
document.write( "X=(8+41.036457)/6<BR>\n" );
document.write( "X=49.036457/6<BR>\n" );
document.write( "X=8.17 INCHES FOR THE SHORTEST SIDE.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );