document.write( "Question 793308: One side of a right triangle is 12 cm long. The hypotenuse is 3 cm more than twice as long as the other side. What are the dimensions of the triangle ? \n" ); document.write( "
Algebra.Com's Answer #480304 by Cromlix(4381)\"\" \"About 
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One side = 12
\n" ); document.write( "Other side = x
\n" ); document.write( "Hypotenuse = 2x + 3
\n" ); document.write( "12^2 + x^2 = (2x + 3)^2
\n" ); document.write( "144 + x^2 = 4x^2 + 12x + 9
\n" ); document.write( "Collect like terms:
\n" ); document.write( "3x^2 + 12x - 135 = 0
\n" ); document.write( "Divide thro'out by 3
\n" ); document.write( "x^2 + 4x - 45 = 0
\n" ); document.write( "(x + 9)(x - 5) = 0
\n" ); document.write( "x + 9 = 0
\n" ); document.write( "x = -9 (no answer as x < 0)
\n" ); document.write( "x - 5 = 0
\n" ); document.write( "x = 5
\n" ); document.write( "Dimensions of triangle:
\n" ); document.write( "One side = 12 cm
\n" ); document.write( "Other side = 5 cm
\n" ); document.write( "Hypotenuse = 13 cm.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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