document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=793256>Question 793256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> eli designed a rectangular garden with length of 5 meters less than twice its width. if the perimeter of the garden is 50 meters, find the dimensions of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480292 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 2w - 5<BR>\n" );
document.write( "width = w<BR>\n" );
document.write( "perimeter = 50\r<BR>\n" );
document.write( "\n" );
document.write( "2(2w - 5) + 2w = 50<BR>\n" );
document.write( "4w - 10 + 2w = 50<BR>\n" );
document.write( "6w - 10 = 50<BR>\n" );
document.write( "6w - 10 + 10 = 50 + 10<BR>\n" );
document.write( "6w = 60<BR>\n" );
document.write( "6w/6 = 60/6<BR>\n" );
document.write( "w = 10\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "2(2(10) - 5) + 2(10) = 50<BR>\n" );
document.write( "2(20 - 5) + 20 = 50<BR>\n" );
document.write( "2(15) + 20 = 50<BR>\n" );
document.write( "30 + 20 = 50<BR>\n" );
document.write( "50 = 50 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );