document.write( "Question 793236: For what values of x is $\"+sqrt+%282x-10%29+\"$ is a real number \n" ); document.write( "

Algebra.Com's Answer #480286 by jim_thompson5910(35256) $\"\"$ $\"About$

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You cannot take the square root of a negative number. Therefore, $\"2x-10\"$ must be 0 or positive, ie \r
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\n" ); document.write( "\n" ); document.write( " $\"2x-10%3E=0\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"2x%3E=10\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%3E=10%2F2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%3E=5\"$ \r
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\n" ); document.write( "\n" ); document.write( "So any number that is 5 or larger for x will make $\"sqrt%282x-10%29\"$ produce a real number.
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