document.write( "Question 793218: How do I find the answer to: Joanne invested four times as much money in an account paying 5% as she did in an account paying 6%. The total amount of interest for the year was $520. How much money did Joanne invest in each account? \n" ); document.write( "
Algebra.Com's Answer #480281 by mananth(16946)\"\" \"About 
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let amount invested at 6% be x\r
\n" ); document.write( "\n" ); document.write( "amount invested at 5% will be 4x\r
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\n" ); document.write( "\n" ); document.write( "Interest = 520\r
\n" ); document.write( "\n" ); document.write( "6%x+5%*4x = 520\r
\n" ); document.write( "\n" ); document.write( "multiply by 100\r
\n" ); document.write( "\n" ); document.write( "6x+20x= 52000\r
\n" ); document.write( "\n" ); document.write( "26x=52000\r
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\n" ); document.write( "x= 2000 @ 6%\r
\n" ); document.write( "\n" ); document.write( "4*2000 = 8000 at 5%\r
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