document.write( "Question 793179: Solve the following linear system using the substitution method and check your solutions.
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document.write( "3x+4y=-6
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document.write( "x-3y=-2 \n" );
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Algebra.Com's Answer #480260 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! x - 3y = -2 \n" ); document.write( "x - 3y + 3y = 3y - 2 \n" ); document.write( "x = 3y - 2 \n" ); document.write( "substitute for x in the first equation \n" ); document.write( "3(3y -2) + 4y = -6 \n" ); document.write( "9y - 6 + 4y = -6 \n" ); document.write( "15y -6 + 6 = -6 + 6 \n" ); document.write( "15y = 0 \n" ); document.write( "15y/15 = 0/15 \n" ); document.write( "y = 0\r \n" ); document.write( "\n" ); document.write( "solve for x \n" ); document.write( "3x + 4(0) = -6 \n" ); document.write( "3x = -6 \n" ); document.write( "3x/3 = -6/3 \n" ); document.write( "x = -2\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "3(-2) + 4(0) = -6 \n" ); document.write( "-6 = -6\r \n" ); document.write( "\n" ); document.write( "-2 - 3(-) = -2 \n" ); document.write( "-2 = -2 \n" ); document.write( " |