document.write( "Question 793100: A certain automobile cooling system contains 11.0 liters of coolant that is 15% antifreeze. How man liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 25% antifreeze will result \n" ); document.write( "

Algebra.Com's Answer #480219 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
L:et $\"+x+\"$ = liters of mixture to be removed
\n" ); document.write( "and replaced with pure antifreeze
\n" ); document.write( "----------------------------
\n" ); document.write( " $\"+.15x+\"$ = liters of pure antifreeze
\n" ); document.write( "in $\"+x+\"$ liters of mixture
\n" ); document.write( "-----------------------
\n" ); document.write( " $\"+.15%2A11+=+1.65+\"$ liters of pure antifreeze in
\n" ); document.write( "original mixture
\n" ); document.write( "-------------
\n" ); document.write( "Note that you end up with the same number
\n" ); document.write( "of liters that you started with
\n" ); document.write( "-------------
\n" ); document.write( " $\"+%28+1.65+-+.15x+%2B+x+%29+%2F+11+=+.25+\"$
\n" ); document.write( " $\"+1.65+%2B+.85x+=+.25%2A11+\"$
\n" ); document.write( " $\"+.85x+=+2.75+-+1.65+\"$
\n" ); document.write( " $\"+.85x+=+1.1++\"$
\n" ); document.write( " $\"+x+=+1.294+\"$ liters
\n" ); document.write( "-------------------
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+%28+1.65+-+.15%2A1.294+%2B+1.294+%29+%2F+11+=+.25+\"$
\n" ); document.write( " $\"+%28+1.65+-+.194+%2B+1.294+%29+%2F+11+=+.25+\"$
\n" ); document.write( " $\"+2.75+%2F+11+=+.25+\"$
\n" ); document.write( " $\"+2.75+=+2.75+\"$
\n" ); document.write( "OK\r
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