document.write( "Question 793000: the base,N,of an antenna rests on horizontal ground. the angle of elecation of the top R, from a point H on the ground is 42(degrees)
\n" ); document.write( "the angle of elevation of R from a second point, G, 6cm closer to N than H, is 53.2(degrees)
\n" ); document.write( "a)calculate
\n" ); document.write( "i)the length of RG
\n" ); document.write( "ii)the height RN, of the antenna
\n" ); document.write( "b)a third point c, lies on the ground 5.4m form N. the angle of depression of CfromR is x degrees
\n" ); document.write( "calculate to the nearest degree the vaule of x
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Algebra.Com's Answer #480211 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
It's all about tangents:
\n" ); document.write( " \"NH=NG%2B6m\"
\n" ); document.write( "\"RN%2FNG=tan%2853.2%5Eo%29=1.3367\" (rounded)
\n" ); document.write( "\"RN%2FNH=RN%2F%28NG%2B6m%29=tan%2842%5Eo%29=0.9004\" (rounded)
\n" ); document.write( "So \"%28NG%2B6m%29%2FNG=1.3367%2F0.9004\" (approximately)
\n" ); document.write( "\"1%2B6m%2FNG=1.4846\" (approximately)
\n" ); document.write( "\"6m%2FNG=0.4846\"
\n" ); document.write( "\"NG=6m%2F0.4846=highlight%2812.38m%29\"
\n" ); document.write( "\"NH=12.38m%2B6m=highlight%2818.38m%29\"
\n" ); document.write( "And since \"RN%2FNH=0.9004\" (rounded) so \"RN=%2818.38m%29%2A0.9004=highlight%2816.55m%29\"
\n" ); document.write( "
\n" ); document.write( "b) \"tan%28%28x%29%29=RN%2FNC=16.55m%2F%225.4+m%22=3.065\" (rounded)
\n" ); document.write( "Since \"tan%2871.93%5Eo%29=3.065\", \"highlight%28x=71.9%5Eo%29\" (approximately)
\n" ); document.write( "
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