document.write( "Question 792025: At the fair, the chickens and the rabbits were placed under the same tent. The chickens and the rabbits have 360 legs. If there were 105 animals how many were rabbits ? \n" ); document.write( "

Algebra.Com's Answer #480198 by Edwin McCravy(20060) $\"\"$ $\"About$

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At the fair, the chickens and the rabbits were placed under the same tent. The chickens and the rabbits have 360 legs. If there were 105 animals how many were rabbits ?
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document.write( "If they were all chickens, there would be only 2×105 or 210 legs.\r\n" );
document.write( "So the extra 360-210 or 150 legs belong to rabbits.  That's 150÷2\r\n" );
document.write( "or 75 pairs of hind legs, so there are 75 rabbits.\r\n" );
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document.write( "You can also do it with algebra:\r\n" );
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document.write( "c + r = 105\r\n" );
document.write( "2c + 4r = 360 \r\n" );
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document.write( "c = 105 - r\r\n" );
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document.write( "2(105-r) + 4r = 360\r\n" );
document.write( "210 - 2r + 4r = 360\r\n" );
document.write( "           2r = 150\r\n" );
document.write( "            r = 75\r\n" );
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document.write( "Edwin

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