document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=792840>Question 792840</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need your help please: How do you find the length of each side of a triangle if the first side of a triangle is 3 meters shorter than the second side, the third side is 4 times as long as the first side and the perimeter is 27 meters?<BR>\n" );
document.write( "This is difficult. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480182 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-3)+x+4(x-3)=27<BR>\n" );
document.write( "x-3+x+4x-12=27<BR>\n" );
document.write( "6x-15=27<BR>\n" );
document.write( "6x=27+15<BR>\n" );
document.write( "6x=42<BR>\n" );
document.write( "x=42/7<BR>\n" );
document.write( "x=7 side 2<BR>\n" );
document.write( "x-3=4 side 1<BR>\n" );
document.write( "4(x-3)=16 side 3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );