document.write( "Question 67483: This is one of my problems that hopefully yall can help me on, \"Tickets for a football game cost $1.00 each if purchased before the day of the game. They cost $1.50 each if bought at the gate. For the homecoming game, 600 tickets were sold, with receipts of $700. How many tickets were sold at the gate?\" Can yall help me please? \n" ); document.write( "
Algebra.Com's Answer #48018 by bam878s(77)\"\" \"About 
You can put this solution on YOUR website!
Let x = number of tickets sold before the game and y = the number of tickets sold the day of the game. Now from the information provided, we know that tickets purchased before the day of the game cost $1.00 and those purchased the day of the game cost $1.50. Also $700 was sold from 600 in sales of tickets. From this information, we have:\r
\n" ); document.write( "\n" ); document.write( "x + y = 600, and
\n" ); document.write( "$1.00(x) + $1.50(y) = $700.\r
\n" ); document.write( "\n" ); document.write( "From the first of these equations we can solve for x
\n" ); document.write( "x + y = 600 ==> x = 600 - y (subtracting y from both sides)\r
\n" ); document.write( "\n" ); document.write( "Now, since we know x, we can plug this into the second equation above
\n" ); document.write( "$1.00(x) + $1.50(y) = $700 ==> $1.00(600-y) + $1.50(y) = $700\r
\n" ); document.write( "\n" ); document.write( "Now multiply the $1.00 into the 600 - y as follows:\r
\n" ); document.write( "\n" ); document.write( "$1.00(600-y) + $1.50(y) = $700 ==> 600 - y + 1.50y = $700
\n" ); document.write( "==> 600 + 0.5y = 700. So now we can solve for y which is the number of tickets sold at the gate!\r
\n" ); document.write( "\n" ); document.write( "600 + 0.5y = 700 (subtract 600 from both sides)
\n" ); document.write( "0.5y = 100 (now divde both sides by 0.5)
\n" ); document.write( "y = 200\r
\n" ); document.write( "\n" ); document.write( "So, there were 200 tickets sold at the gate. You could also figure out how many were sold before the game day by plugging this value of y into one of the original equations and solving for x, but this is not required in the question. Only need to solve for y (the number of tickets sold at the gate)\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!!
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