document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67485>Question 67485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> g(x)=3x-4<BR>\n" );
document.write( "find the functional value of <BR>\n" );
document.write( "g(2a+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48015 by </B><A HREF=/tutors/aboutme.mpl?userid=bam878s><B>bam878s(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bam878s><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given g(x)=3x-4.  To solve g(2a+1) all we need to do is to plug 2a+1 into the original equation for x and simplify!\r<BR>\n" );
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document.write( "g(2a+1) = 3(2a+1)-4  ------> Multiply the 3 into 2a+1\r<BR>\n" );
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document.write( " = [3(2a) + 3(1)] - 4<BR>\n" );
document.write( " = 6a + 3 - 4<BR>\n" );
document.write( " = 6a - 1. \r<BR>\n" );
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document.write( "Hope this helps!! </SPAN>\n" );
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