document.write( "Question 792812: An object is projected vertically upward with an initial velocity of Vo ft/sec, and its distance s(t) in feet above the ground after t seconds is given by the formula s(t)=-16t^2+Vot.\r
\n" );
document.write( "\n" );
document.write( "a) if the object hits the ground after 12 seconds, find its initial velocity.
\n" );
document.write( "B) find its maximum distance above the ground. \n" );
document.write( "
Algebra.Com's Answer #480142 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An object is projected vertically upward with an initial velocity of Vo ft/sec, and its distance s(t) in feet above the ground after t seconds is given by the formula \n" ); document.write( "s(t)=-16t^2+Vot\r \n" ); document.write( "\n" ); document.write( "a) if the object hits the ground after 12 seconds, find its initial velocity. \n" ); document.write( "Solve: 0 = -16*12^2 + Vo*12 \n" ); document.write( "------ \n" ); document.write( "12Vo = 16*12^2 \n" ); document.write( "Vo = 16*12 \n" ); document.write( "Vo = 152 ft/sec \n" ); document.write( "========================== \n" ); document.write( "B) find its maximum distance above the ground. \n" ); document.write( "s(t)=-16t^2+Vot \n" ); document.write( "s(t) = -16t^2 + 152t \n" ); document.write( "--- \n" ); document.write( "Max height occurs when t = -b/(2a) = -152/(2*-16) = 4.75 \n" ); document.write( "Max height = s(4.75) = -16(4.75)^2 + 152(4.75) = 361 ft \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================= \n" ); document.write( " \n" ); document.write( " |