document.write( "Question 792757: How is three-fourths x minus 45=0 become 0? \r
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document.write( "The full equation is 11/12 x-12=1/6x+33 \n" );
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Algebra.Com's Answer #480141 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! How is three-fourths x minus 45=0 become 0? \n" ); document.write( "(3/4)x - 45 = 0 \n" ); document.write( "(3/4)x = 45 \n" ); document.write( "(1/4)x = 15 \n" ); document.write( "x = 60 \n" ); document.write( "----------------- \n" ); document.write( "The full equation is 11/12 x-12=1/6x+33 \n" ); document.write( "------------ \n" ); document.write( "11x/12 - 12 = x/6 + 33 \n" ); document.write( "Multiply by 12 to eliminate fractions \n" ); document.write( "11x - 144 = 2x + 396 \n" ); document.write( "9x = 540 \n" ); document.write( "x = 60 \n" ); document.write( " \n" ); document.write( " |