document.write( "Question 792757: How is three-fourths x minus 45=0 become 0? \r
\n" ); document.write( "\n" ); document.write( "The full equation is 11/12 x-12=1/6x+33
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Algebra.Com's Answer #480141 by Alan3354(69443)\"\" \"About 
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How is three-fourths x minus 45=0 become 0?
\n" ); document.write( "(3/4)x - 45 = 0
\n" ); document.write( "(3/4)x = 45
\n" ); document.write( "(1/4)x = 15
\n" ); document.write( "x = 60
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\n" ); document.write( "The full equation is 11/12 x-12=1/6x+33
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\n" ); document.write( "11x/12 - 12 = x/6 + 33
\n" ); document.write( "Multiply by 12 to eliminate fractions
\n" ); document.write( "11x - 144 = 2x + 396
\n" ); document.write( "9x = 540
\n" ); document.write( "x = 60
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