document.write( "Question 792749: ln e^(log(x+1)+log(x-2)) = (1/2)e^(ln(2)), what is x? \n" ); document.write( "
Algebra.Com's Answer #480127 by lwsshak3(11628)\"\" \"About 
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ln e^(log(x+1)+log(x-2)) = (1/2)e^(ln(2)), what is x?
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\n" ); document.write( "log of base raised to a power=power
\n" ); document.write( "ln e^(log(x+1)+log(x-2))=log(x+1)+log(x-2)=log(x+1)(x-2)
\n" ); document.write( "..
\n" ); document.write( "Base raised to the log of number=number
\n" ); document.write( "(1/2)e^(ln(2))=(1/2)*2=1
\n" ); document.write( "..
\n" ); document.write( "log(x+1)(x-2)=1
\n" ); document.write( "10^1=(x+1)(x-2)
\n" ); document.write( "10=x^2-x-2
\n" ); document.write( "x^2-x-12=0
\n" ); document.write( "(x-4)(x+3)=0
\n" ); document.write( "x=4
\n" ); document.write( "or
\n" ); document.write( "x=-3
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