document.write( "Question 792749: ln e^(log(x+1)+log(x-2)) = (1/2)e^(ln(2)), what is x? \n" ); document.write( "
Algebra.Com's Answer #480127 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! ln e^(log(x+1)+log(x-2)) = (1/2)e^(ln(2)), what is x? \n" ); document.write( "*** \n" ); document.write( "log of base raised to a power=power \n" ); document.write( "ln e^(log(x+1)+log(x-2))=log(x+1)+log(x-2)=log(x+1)(x-2) \n" ); document.write( ".. \n" ); document.write( "Base raised to the log of number=number \n" ); document.write( "(1/2)e^(ln(2))=(1/2)*2=1 \n" ); document.write( ".. \n" ); document.write( "log(x+1)(x-2)=1 \n" ); document.write( "10^1=(x+1)(x-2) \n" ); document.write( "10=x^2-x-2 \n" ); document.write( "x^2-x-12=0 \n" ); document.write( "(x-4)(x+3)=0 \n" ); document.write( "x=4 \n" ); document.write( "or \n" ); document.write( "x=-3 \n" ); document.write( " |