document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=792477>Question 792477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to find the length and the width of the rectangle if the diagonal is 7<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #480046 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=480046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean Theorem.\r<BR>\n" );
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document.write( "Let x represent the length and width. If x represents the length and width, this means that your shape is actually a square NOT a rectangle. Why? Because a square has EQUAL MEASURE on all four sides.\r<BR>\n" );
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document.write( "Let d represent the diagonal.\r<BR>\n" );
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document.write( "x^2 + x^2 = d^2\r<BR>\n" );
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document.write( "2x^2 = 7^2\r<BR>\n" );
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document.write( "2x^2 = 49\r<BR>\n" );
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document.write( "x^2 = 49/2\r<BR>\n" );
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document.write( "sqrt{x^2} = sqrt{49/2}\r<BR>\n" );
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document.write( "x = 7/sqrt{2}\r<BR>\n" );
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document.write( "You may rationalize the denominator. If you do, the answer for x is<BR>\n" );
document.write( "7(sqrt{2})/2. This is the measure of the length and width, which means this figure is actually a square not a rectangle. \r<BR>\n" );
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document.write( "How do we read 7(sqrt{2})/2? \r<BR>\n" );
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document.write( "The length and width is 7 times the square root of 2 divided by 2. \r<BR>\n" );
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